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9x^2-90x+144=0
a = 9; b = -90; c = +144;
Δ = b2-4ac
Δ = -902-4·9·144
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-54}{2*9}=\frac{36}{18} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+54}{2*9}=\frac{144}{18} =8 $
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